Sample questions
5 of the 220 questions in this chapter. Answers and solutions open below each one.
Question 1 of 5, NEET levelSubatomic particles, atomic models, nucleus
In the gold foil experiment, a very small fraction of the alpha particles bounced back through large angles. Which conclusion was drawn mainly from this observation?
- AElectrons are embedded uniformly in a sphere of positive charge
- BPositive charge and most of the mass of the atom are concentrated in a very small central region
- CElectrons move only in orbits of fixed energy
- DAlpha particles are heavier than the atoms of gold
Answer and solution
Answer: B. Large-angle reflection of a few heavy, positive alpha particles needs a strong repulsion from a tiny, massive, positively charged centre. A uniform positive sphere (Thomson model) cannot produce such deflections. Hence the nucleus concept.
Question 2 of 5, NEET levelQuantum theory of light and photoelectric effect
Among the following radiations, the photon of which has the highest energy?
- AInfrared
- BMicrowave
- CGreen light
- DUltraviolet
Answer and solution
Answer: D. Photon energy E = h nu is proportional to frequency. Of the four regions, ultraviolet has the highest frequency (shortest wavelength), so its photons carry the most energy.
Question 3 of 5, NEET levelBohr model: energy, radius, velocity, ionisation energy
The energy of the electron in the n=2 level of a hydrogen atom, taking E1=−13.6 eV, is
- A−13.6 eV
- B−6.8 eV
- C−3.4 eV
- D−1.51 eV
Answer and solution
Answer: C. For hydrogen En=E1/n2. For n=2: E2=−13.6/4=−3.4 eV.
Question 4 of 5, NEET levelHydrogen spectrum and spectral series
The lines of the Lyman series in the hydrogen spectrum lie in the
- Aultraviolet region
- Bvisible region
- Cinfrared region
- Dmicrowave region
Answer and solution
Answer: A. Lyman lines arise from transitions to n=1, the largest energy gaps in hydrogen (10.2 eV to 13.6 eV), so their wavelengths (about 91 nm to 122 nm) are in the ultraviolet.
Question 5 of 5, NEET levelde Broglie wavelength and uncertainty principle
If the speed of a moving electron is doubled while its mass stays the same, its de Broglie wavelength
- Aremains unchanged
- Bbecomes double
- Cbecomes half
- Dbecomes one-fourth
Answer and solution
Answer: C. Since λ=h/(mv), the wavelength is inversely proportional to speed. Doubling v halves λ.
How to use this chapter
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